2(x^2+4)=-20

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Solution for 2(x^2+4)=-20 equation: 



2(x^2+4)=-20

We move all terms to the left:

2(x^2+4)-(-20)=0

We add all the numbers together, and all the variables

2(x^2+4)+20=0

We multiply parentheses

2x^2+8+20=0

We add all the numbers together, and all the variables

2x^2+28=0

a = 2; b = 0; c = +28;
Δ = b2-4ac
Δ = 02-4·2·28
Δ = -224
Delta is less than zero, so there is no solution for the equation

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